When a method in a derived class has:
string in the base class and object in the derived class)
the result is that the base method becomes hidden.
As shown in the following code snippet, when an instance of the derived class is used, invoking the method with an argument that matches the less derived parameter type will invoke the derived class method instead of the base class method:
class BaseClass
{
internal void MyMethod(string str) => Console.WriteLine("BaseClass: Method(string)");
}
class DerivedClass : BaseClass
{
internal void MyMethod(object str) => Console.WriteLine("DerivedClass: Method(object)"); // Noncompliant
}
// ...
BaseClass baseObj = new BaseClass();
baseObj.MyMethod("Hello"); // Output: BaseClass: Method(string)
DerivedClass derivedObj = new DerivedClass();
derivedObj.MyMethod("Hello"); // Output: DerivedClass: Method(object) - DerivedClass method is hiding the BaseClass method
BaseClass derivedAsBase = new DerivedClass();
derivedAsBase.MyMethod("Hello"); // Output: BaseClass: Method(string)
class BaseClass
{
internal void MyMethod(string str) => Console.WriteLine("BaseClass: Method(string)");
}
class DerivedClass : BaseClass
{
internal void MyOtherMethod(object str) => Console.WriteLine("DerivedClass: Method(object)"); // Compliant
}
// ...
BaseClass baseObj = new BaseClass();
baseObj.MyMethod("Hello"); // Output: BaseClass: Method(string)
DerivedClass derivedObj = new DerivedClass();
derivedObj.MyMethod("Hello"); // Output: BaseClass: Method(string)
BaseClass derivedAsBase = new DerivedClass();
derivedAsBase.MyMethod("Hello"); // Output: BaseClass: Method(string)
Keep in mind that you cannot fix this issue by using the new keyword or by marking the method in the base
class as virtual and overriding it in the DerivedClass because the parameter types are different.
The rule is not raised when the two methods have the same parameter types.